Mathematics: Aproton at the large hadron collider at cern travels at 295,000,000 meters per second. how long does it take the proton to go around the 17 mile circumference of the collider?

Aproton at the large hadron collider at cern travels

Ответ:

samariahmiddlebrooks

11.03.2022

Mathematics

9.27 x 10^-5 seconds

Step-by-step explanation:

We are given the speed of the proton at which it travels i.e. 295,000,000 meters per second.

And we also know the total circumference of the collider = 17 mile.

So to find the time taken the proton to travel around the circumference of the collider, we first need to make the units same.

1 mile = 1609.34 meters

17 mile = 1609.34 * 17 = 27358.78

Time taken by the proton = distance / speed

= 27358.78 / 295000000

= 9.27 x 10^-5

Therefore, it takes 9.27 x 10^-5 or 0.0000927 seconds for the proton to go around 17 mile circumference of the collider.

0,0(0 оценок)

Ответ:

googoo4

16.04.2021

Mathematics

$C(d) = \frac{1}{5}d + 320$

Step-by-step explanation:

Given

$d \to miles$

$C \to cost$

So:

(d_1,C_1) = (500,420) --- May

(d_2,C_2) = (620,444) --- June

Required

Express as a function

Start by calculating the slope (m)

$m = \frac{\triangle C}{\triangle d}$

$m = \frac{444-420}{620-500}$

$m = \frac{24}{120}$

Simplify

$m = \frac{1}{5}$

The equation is:

C(d) = m(d - d_1) +C_1

$C(d) = \frac{1}{5}(d - 500) +420$

$C(d) = \frac{1}{5}d - 100 +420$

Take LCM

$C(d) = \frac{1}{5}d + 320$

0,0(0 оценок)

Aproton at the large hadron collider at cern travels at 295,000,000 meters per second. how long does it take the proton to go around the 17 mile circumference of the collider?

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Mathematics

Ask an AI advisor a question