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BaileyElizabethRay
18.01.2020 •
Mathematics
Apublisher reports that 79% of their readers own a laptop. a marketing executive wants to test the claim that the percentage is actually more than the reported percentage. a random sample of 350 found that 82% of the readers owned a laptop. is there sufficient evidence at the 0.01 level to support the executive's claim?
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Ответ:
There is sufficient evidence at the 0.01 level to support the executive's claim
Step-by-step explanation:
Given that a publisher reports that 79% of their readers own a laptop. A marketing executive wants to test the claim that the percentage is actually more than the reported percentage
Sample size n =350
Sample proportion P =0.82
(right tailed test at 1% level of significance for proportions)
Assuming H0 to be true i.e. p = 0.79, std error of sample proporiton
=![\sqrt{\frac{0.79*0.21}{250} } \\=0.02576\\](/tpl/images/0460/1364/56077.png)
p difference =![0.82-0.79=0.03](/tpl/images/0460/1364/785e6.png)
test statistic Z=p diff/std error
=1.1646
p value = 0.1221
Since p value >0.01, our significant value, we fail to reject H0
There is sufficient evidence at the 0.01 level to support the executive's claim
Ответ: