Apyramid with a square base of length 3cm and height 16cm

H = 16 cm
s = 16.0702 cm
a = 3 cm
e = 16.14 cm
r = 1.5 cm
V = 48 cm3
L = 96.421 cm2
B = 9 cm2
A = 105.421 cm2

The volume of a square pyramid:V = (1/3)a2hSlant Height of a square pyramid:By the Pythagorean theorem, we know thats2 = r2 + h2since r = a/2s2 = (1/4)a2 + h2, ands = √(h2 + (1/4)a2)This is also the height of a triangle sideLateral Surface Area of a square pyramid (4 isosceles triangles):For the isosceles triangle Area = (1/2)Base x Height. Our base is side length a, and for this calculation our height for the triangle is slant height s.  With four
 sides we need to multiply by 4.L = 4 x (1/2)as = 2as = 2a√(h2 + (1/4)a2)Squaring the 2 to get it back inside the radical,L = a√(a2 + 4h2)Base Surface Area of a square pyramid (square):B = a2Total Surface Area of a square pyramid:A = L + B = a2 + a√(a2 + 4h2))A = a(a + √(a2 + 4h2))

Use PEMDAS (Parenthesis/groupings, Exponent, Multiplication/Division [which ever comes first], Addition/Subtraction [which ever comes first]) as priority rule. Run the equation always from leftmost to rightmost

[(7 + 3) • 5 – 4] ÷ 2 + 2     ---> our equation
[10 • 5 – 4] ÷ 2  + 2          ---> since innermost parenthesis/grouping
[50 – 4] ÷ 2  + 2               ---> since multiplication and inside a grouping
46 ÷ 2  + 2                       ---> since inside a grouping
23  + 2                             ---> since division
25                                    ---> final answer