Aquadrilateral has vertices (5, 3), (5, -1), (-1, 3), and (-1, -1(. what special quadrilateral is formed by connecting the midpoints of the sides?

The four vertices of the new quadrilateral is the midpoints of the four sides. (5,3) and (5,-1) is ((5+5)/2,(3-1)/2)=(5,1). Midpoint between (-1,3) and (5,3)=(2,3). Midpoint between (-1,3) and (-1,-1) is (-1,1). Midpoint between (-1,-1) and (5,-1) is (2,-1). So the four vertices are (5,1), (2,3), (-1,1), and (2,-1). The resulting figure is a rhombus, centered at (2,1).

3/5 = sin(b)

Step-by-step explanation:

Equation

Tan(b) = sin(b)/cos(b)                         Multiply both sides by cos(b)

cos(b)*tan(b) = cos(b)sin(b)/cos(b)    Simplifiy

cos(b)*tan(b) = sin(b)

Givens

Tan(b) = 3/4

Cos(b) = 4/5

Solution

4/5 * 3/4 = sin(b)

12/20 = sin(b)

3/5     = sin(b)