Aradio station broadcasts a signal over qn area with a radius of 50 miles. the station can relay the signal and broadcast over an area with a radius of 75 miles. how much greater is the area of the broadcast region when the signal is relayed? round your answer to tje nearest sqaure mile

A = pi * r^2 
A = 3.14 * 50^2 
A = 7,850 square miles (area of the 50 mile broadcast signal)

A = pi * r^2
A = 3.14 * 75^2
A = 17,662.5 = 17,663 square miles (area of the 75 mile relayed signal)

Now we just need to subtract the 50 mile signal from the 75 mile signal, so:

17,663 - 7,850 = 9,813 square miles greater

Hope this helps :)

M=3/2

Step-by-step explanation:

Convert to slope-intercept form.

subtract 3x from both sides:

3x-2y=10

-3x      -3x

the threes will cancel out leaving you with:

-2y=10-3x

then divide both sides by -2:

-2y=10-3x

-2y   -2

your twos will then cancel out leaving you with:

y=-5-3/2

your answer is then:

3/2

heres a formula you can go by:

y=mx+b. m is the slope and b is the y-intercept.

I hope this helps :)

Step-by-step explanation: