pr4ever
06.07.2019 •
Mathematics
Arectangle has a perimeter of 204 feet. it's length is six feet longer than twice it's width. if l stands for the length of the rectangle and w stands for its width, write a system of equations that models the information given in this problem and solve it to find the length and width of this rectangle
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Ответ:
L = 70
W = 32
Step-by-step explanation:
P = 2L + 2W
P 204 feet
W = x
L = 2x + 6
P = 2L + 2W
P = 2*(2x + 6) + 2*x
P = 4x + 12 + 2x
P = 6x + 12
But we know that P = 204 So 6x + 12 = 204
6x + 12 = 204 Subtract 12 from both sides
6x + 12 - 12 = 204 - 12 Collect like terms on the right
6x = 192 Divide by 6
x = 192/6
x = 32
Answer
W = 32
L = 2*W + 6
L = 2*32 + 6
L = 64 + 6
L = 70
Ответ:
It's B because a dotted lined line represents <, > and a straight line represents ≤, ≥