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ajj3233
23.07.2019 •
Mathematics
Arectangle is 13 meters longer than it is wide. the perimeter is 98 meters. what is the width?
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Ответ:
To solve this problem, let's make two equations:
Let x be the rectangle's length.
Let y be the rectangle's width.
x = y + 13
2x + 2y = 98
Now, since x equals y + 13, we can substitute the value of x into the equation 2x + 2y = 98:
2x + 2y = 98
2(y + 13) + 2y = 98
2y + 26 + 2y = 98
4y = 98 - 26
4y = 72
y = 18
Now, let's plug the value of y into the equation to find x:
x = y + 13
x = 18 + 13
x = 31
So, the length is 31 and the width is 18.
Hope this helps!
Ответ:
279936
Step-by-step explanation:
Hope this helps!