Arectangle's length is 3 cm more than twice its width. if the perimeter is 48 cm, what is the
rectangle's area?

119 square centimeters.

Step-by-step explanation:

Write the problem as an equation.

2(2x+3)+2x=48

Where x is width of the rectangle. 2x+3 represents the length.

4x+6+2x=48

6x+6=48

6x=42

x=7

The width is 7 cm.   Then, find the length.

(2x+3)     Given

(2)(7)+3   Plug in 7 for x

14+3

17

Then, find the area, width*length

17*7=119

113°

Step-by-step explanation:

53+6+8= 67

180-67=113