marbuigues9171
25.12.2019 •
Mathematics
Arectangle warehouse will have 5000 square feet of floor space and will be separated into two rectangular rooms by an interior wall. the cost of the exterior walls is $150 per linear foot and the cost of the interior wall is $100 per linear foot. find the dimensions that will minimize the cost of building the warehouse.
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Ответ:
x = 59.4 ft
y = 84.18ft
Step-by-step explanation:
The cost of exterior walls is $150 per linear foot.
The cost of interior walls is $100 per linear foot.
xy = 5000
y = 5000/x
For the exterior walls, we have 2(x+y)(120)
For the interior wall, we have 100x
The cost function = C
C = 2(x+y)(120) + 100x
C= 240(x+y) + 100x
= 240x + 240y + 100x
= 340x + 240y
Recall that y = 5000/x
C = 340x + 240(5000/x)
C = 340x + 1200000/x
Differentiate C with respect to x
C'(x) = 340 - 1200000/x^2
= (340x^2 -1200000) / x^2
To minimize cost C'(x) = 0
(340x^2 -1200000) / x^2 = 0
340x^2 -1200000 = 0
340x^2 = 1200000
x^2 = 1200000/340
x = √1200000/340
x = 59.4 ft
Recall that y = 5000/x
y = 5000/59.4
y = 84.18 ft
Ответ: