Mathematics: Arectangular box is 10 in. wide, 10 in. tall, and 8 in. long. what is the diameter of the smallest circular opening through which the box will fit?

Arectangular box is 10 in. wide, 10 in. tall, and - id101084340296, missdakotacheyenne

bricefitzpatrick0429

13.01.2022

Diameter of smallest circular opening = 12.81 in

Step-by-step explanation:

Given:-

Width of rectangular box(W)=10 in.

Length of rectangular box(L)=8 in.

Height of rectangular box(H)=10 in.

For box to fit in the smallest circular opening we need to find the diagonal of the rectangular box, therefore

diagonal of rectangular box=diameter of smallest circular opening

So,

$Diagonal\ (d)=\sqrt{width^{2}+length^{2} }$

$d=\sqrt{W^{2} +L^{2} }$

$d=\sqrt{10^{2}+8^{2}}$

$d=\sqrt{100+64}$

$d=\sqrt{164}$

$d=12.81\ in.$

$\therefore\ diagonal\ (d)=12.81\ in$

Therefore diameter of smallest circular opening = 12.81 in.

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Nweze1760

03.05.2023

c=number o cats

d=number o dogs

has 9 fewer dogs than cats means c-9=d

has total o 15 dogs, so find cats

if d=15

c-9=15

add 9 to both sides

c=24

24 cats

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