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katlian
02.09.2019 •
Mathematics
Aregular triangular pyramid has a base and lateral faces that are congruent equilateral triangles. it has a lateral surface area of 57 square centimeters. what is the surface area of the regular triangular pyramid?
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Ответ:
57/3= 19 cm^2 per side. Because the base is equal to the area of the side, this is the base area.
19+57= 76 cm^2 for sides+ base (total surface area)
Final 76 cm^2
Ответ:
See explanation
Step-by-step explanation:
Area of one rectangle: l × w
7 × 4 = 28
28 in²
Total area: 28 × 4 = 112
112 in²