Aright triangle has an area of 24ft^2. the dimensions

Ответ:

queenkimm26

10.03.2022

$864\ ft^2$

Step-by-step explanation:

we know that

The area of a triangle is equal to

$A=\frac{1}{2}bh$

$A=24\ ft^2$

$24=\frac{1}{2}bh$ -------> 48=bh ------> equation A

where

b is the base of the triangle

h is the height of the triangle

In this problem the dimensions of the triangle are increased by a scale factor of

the new dimensions of the triangle are

b=6b, h=6h

The new area of the triangle will be

$A1=\frac{1}{2}(6b)(6h)$

A1=18bh ------> equation B

Substitute equation A in equation B

$A1=18[48]=864\ ft^2$

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