As an alternative to the use of father’s height to predict son’s height, Gallon also used the midparent height, the average of the father’s and mother’s heights. Here are the heights of nine female students along with their midparent heights in inches: Midparent 66.0 65.5 71.5 68.0 70.0 65.5 67.0
Daughter 64.0 63.0 69.0 69.0 69.0 65.0 63.0
Midparent 70.5 69.5 64.5 67.5
Daughter 68.5 69.0 64.0 67.0
a. Make a scatter plot of daughter’s height against the midparent height and comment on the strength of the relationship.
b. Is the daughter’s height completely and uniquely determined by the midparent height? Explain.
c. Use the accompanying MINITAB output to obtain the equation of the least squares line for predicting daughter height from midparent height and then predict the height of a daughter whose midparent height is 70 inches. Would you feel comfortable using the least squares line to predict daughter height when midparent height is 74 inches? Explain.

What we know:
shape is rectangle which means the 2 long sides have equal distance and the 2 short sides have equal distance
we just need to find the distance of one long side and one short side for the perimeter which is the outline of the rectangle. Imagine the perimeter is the fence around the rectangle  that you would probably have to paint every 3 years and the area would be where the grass would grow in the rectangle which you would probably have to cut every weekend.

perimeter=2l+2w
 
What we need to find: PERIMETER
Using pythagorean method a² +b²=h² to find length:
From point (-6,1) to point (3,8) is a rise of 9 and a run of 9 right to get from one point to another, those are my a and b in the pythagorean formula.
a² +b²=h²
(9)²+(9)²=h²         substitution
81+81=h²            simplified
162=h²
√162=√h2           used radical properties
√162=h               length =√162

Using pythagorean method a² +b²=h² to find width:
From points (-6,-1) to point (-3,-4) is a down 3 units and left 3 units to reach from one point to another, these are my a and b for the pythagorean formula.

a² +b²=h²
(3)²+(3)²=h²
9+9=h²
18=h²
√18=√h²
√18=h           this is the width=√18

Now we find perimeter:
p=2l+2w
p=2(√162)+2(√18)
p≈33.9

D. 33.9 units