As of a certain date, 94,696 of the four-character sequences using either letters or digits had not yet been claimed. If a four-character name is randomly selected on that date, what is the probability that it is already owned? (Round your answer to four decimal places.)

Hence the probability that are already owned are 0.943620

Step-by-step explanation:

Given:

No fo character sequences using either letter or digits had not been claimed=94696

To find :

What is probability that letter are already claimed ?

Solution:

We know that there are 26 alphabets  and digits are 0,1,2.. 9

Hence total will be of 36.

Now we are going to Arrange the sequence for all possible values

as there 4 characters we get ,each of them with 36 possible values

=36*36*36*36

=36^4

=1679616.

Now we have a sequence with 94696 character and digits are not claimed .

Its probability

=94696/1679616

=0.05637.

So the required probability will be ,

P(claimed)=1- P(Not claimed)

= 1-0.056379

=0.943620

Hence the probability that are already owned are 0.943620

b = d -wn

Step-by-step explanation:

b = d -wn

Here, n is an independent variable and b is an dependent variable in an linear relation, and d and w are two constant values.

Hope it will find you well.