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Abbymay17
12.01.2021 •
Mathematics
Asako deposits $1000 into a bank account that pays 1.5% interest compounded annually. Which inequality can she use to determine the minimum time in years t she needs to wait before the value of the account is 20% more than its original value?
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Ответ:
Option D
Step-by-step explanation:
Given question is incomplete; here is the complete question.
Asako deposits $1000 into a bank that pays 1.5% interest compounded annually. Which inequality can she use to determine the minimum time in years 't' she needs to wait before the value of the account is 20% more than its original value?
A. 1000 . 1.01t > 1200
B. 1000 . 1.01t > 1.2
C.![1.015^t1200](/tpl/images/1028/8045/87b8b.png)
D.![1.015^t1.2](/tpl/images/1028/8045/465f7.png)
Formula to get the final amount by compounding is,
Final amount =![\text{Initial amount}\times(1+\frac{r}{n})^{nt}](/tpl/images/1028/8045/aff7b.png)
Here, r = rate of interest
n = number of compounding in a year
t = Time or duration of investments (In years)
Initial amount = $1000
Final amount = 20% more than its original value = $(1000 + 0.2×1000) = $1200
r = 1.5% = 0.015
Inequality that represents the final amount 20% more than the initial value,
Therefore, Option D will be the correct option.
Ответ:
y is less than or equal to -1
How?
The graphs highest value it will ever reach, range wise, is -1. Therefore it isnt 0, or all real numbers.
The reason why it is -1 and not -2 is because the curve hits -1. Sure, -2 is included in the range, but y is less than or equal to -1 INCLUDES -2
:)