Asandwich shop loses $1.20 every time somebody buys a sandwich, but makes $1.80 every time somebody buys a drink. one day, the shop sells 100 drinks, and makes a profit of over $100. which are possible numbers of sandwiches the shop could have sold? check all that apply.

a. 0 sandwiches
b. 40 sandwiches
c. 60 sandwiches
d. 70 sandwiches
e. 80 sandwiches

A, B, and C

I think. Please let me know if wrong.

Heres what i did:

1.8 x 100 = 180.

180 - 80 = 100

(they made over 10 in profit)

A. 1.2 x 0 = 0

B. 1.2 x 40 - 48

C. 1.2 x 60 = 72

D. 1.2 x 70 = 84

E. 1.2 x 80 =96

D and E bot Exceed 80 so it has to be AB and C

Hope this Helps ☺

A,b,c

Step-by-step explanation:

P=1.8d-1.2s

P=180-1.2s

100=180-1.2s

-80=-1.2s

66.7=s

If they sold ≥67 sandwiches, p<100

If they sold ≤66 sandwiches, p>100

Therefore A, B and C are correct

To multiply fractions you have to move to the left so multiply the numerator by the numerator and the denominator by the denominator.

Now reduce:

(optional) Change into a mixed number:

The answer is "1 3/8 or 11/8."

Hope this helps.