Asawhat is the equation of the following graph in vertex form? y = (x - 4)2 - 4y = (x + 4)2 - 4y = (x + 2)2 + 6y = (x + 2)2 + 12

y =(v-4)^2 -4

Step-by-step explanation:

vertex form of a parabola is

y = a (v-h)^2 +k

where (h,k) is the vertex

y =a(v-4)^2 +(-4)

y =a(v-4)^2 -4

now substitute another point in to determine a

let's pick 0, 12

12 = a((0-4)^2 -4

add 4 to each side

16 = a * (-4)^2

16 = a*16

divide by 16

a = 1

substitute in what we know

y =1 *(v-4)^2 -4

y =(v-4)^2 -4