Mathematics: Asequence is defined by the recursive function f(n+1)=1/3f(n). if f(3)=9, what is f(1)? 1 3 27 81 i will give !

Asequence is defined by the recursive function f(n+1)=1/3f(n).

Ответ:

markarianlaura1

14.01.2022

Mathematics

Step-by-step explanation:

$f(n+1)=\frac{1}{3}f(n)$ means a term can be found by multiplying previous term by $\frac{1}{3}$ .

So if we want to go backwards to find the previous term from a term that comes after it we need to multiply that by .

This means:

f(3)=9 implies f(2)=3(9)=27 .

f(2)=27 implies f(1)=3(27)=81 .

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Another way to look at it:

$f(n+1)=\frac{1}{3}f(n)$

Multiply both sides by 3:

3f(n+1)=f(n)

By the symmetric property:

f(n)=3f(n+1)

So if n=2 :

f(2)=3f(2+1)

f(2)=3f(3)

f(2)=3(9)=27

If n=1 :

f(1)=3f(1+1)

f(1)=3f(2)

f(1)=3(27)=81 .

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Ответ:

rosie81

15.07.2021

Mathematics

The answer in the procedure

Step-by-step explanation:

we know that

If the dilation produces a smaller figure

then

the scale factor must be less than one

Let

z > the scale factor

z < 1

A possible scale factor can be 0.50, 0.20,0.35,0.80, etc

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Asequence is defined by the recursive function f(n+1)=1/3f(n). if f(3)=9, what is f(1)?
1
3
27
81

i will give !

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