Mathematics: Ashley has $9.05 in dimes and nickels. If she has a total of 108 coins, how many of each type does she have?

W+1=larea=lwarea=(w+1)w1500=w²+wminus 1500 both sides0=w²+w-1500use quadratic formulaforaw²+bw+c=077.466121627457250675410729387462it can t be minus since measures cannot be negativew=38.233060813728625337705364693731to nearest wholew=38l=38+1=39the dimentions are 38 by 39 inches...

Ashley has $9.05 in dimes and nickels. If she has - id90510422666, manuellopez1981

Ответ:

DatBoiCedd

17.03.2022

Mathematics

$73\:\mathrm{dimes},\\35\:\mathrm{nickels}$

Step-by-step explanation:

We can write the following system of equations:

$\begin{cases}10d+5n=905,\\d+n=108,\\\end{cases}$ , where is the number of dimes she has and is the number of nickels she has.

Multiply the second equation by and add both equations to solve for :

$\begin{cases}10d+5n=905,\\-5d-5n=-540,\\\end{cases}\\5d=365,\\d=\fbox{$73$}$ .

Plug d=73 into any equation to solve for :

$73+n=108, \\n=\fbox{$35$}$

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Ответ:

htorres2p8urw0

21.09.2022

Mathematics

W+1=l
area=lw
area=(w+1)w
1500=w²+w
minus 1500 both sides
0=w²+w-1500
use quadratic formula
for
aw²+bw+c=0
$w= \frac{-b+/- \sqrt{b^2-4ac} }{2a}$

$w= \frac{-(1)+/- \sqrt{1^2-4(1)(-1500)} }{2(1)}$
$w= \frac{-1+/- \sqrt{1+6000} }{2}$
$w= \frac{-1+/- \sqrt{6001} }{2}$
77.466121627457250675410729387462
$w= \frac{-1+/- 77.466121627457250675410729387462}{2}$
it can't be minus since measures cannot be negative
$w= \frac{-1+ 77.466121627457250675410729387462}{2}$
$w= \frac{76.466121627457250675410729387462}{2}$
w=38.233060813728625337705364693731
to nearest whole
w=38
l=38+1=39

the dimentions are 38 by 39 inches

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Ashley has $9.05 in dimes and nickels. If she has a total of 108 coins, how many of each type does she have?

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