Asoccer ball is kicked with a speed of 8.50 m/s at an angle of 28.0° above the horizontal. if the ball lands at the same level from which it was kicked, how long was it in the air? (neglect air resistance.)

Upward velocity at launch= 8.50*sin280

                                                                   8.50×0.4694

                                         =3.989

Time taken to reach maximum height=v/g

                                      =3.9899/9.8

Same speed to needed to come down,

So, time in air= 3.9899/4.9

                     =0.81 sec

Question:

Examine the graph.

Select each interval where the graph is increasing.

2 < x < 3

−1 < x < 0

−3 < x < -2

0 < x < 1

The image of the graph is attached below:

Option A:

Option C:

Explanation:

Option A:

From the graph, we can see that the interval , the graph is increasing. An increasing graph raises from left to right.

Thus, in the interval the graph is increasing.

Hence, Option A is the correct answer.

Option B:

From the graph, we can see that the interval , the graph is decreasing. A decreasing graph decreases from left to right.

Thus, in the interval the graph is decreasing.

Hence, Option B is not the correct answer.

Option C:

From the graph, we can see that the interval , the graph is increasing. An increasing graph raises from left to right.

Thus, in the interval the graph is increasing.

Hence, Option C is the correct answer.

Option D:

From the graph, we can see that the interval , the graph is decreasing. A decreasing graph decreases from left to right.

Thus, in the interval the graph is decreasing.

Hence, Option D is not the correct answer.