Mathematics: Asparrow flies to see a friend at a speed of 4km/h. his friend is out, so the sparrow immediately returns home at a speed of 5km/h. the complete journey took 54 minutes. how far away does his friend live?

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Asparrow flies to see a friend at a speed of - id44597946, dontcareanyonemo

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shanice13

15.01.2022

2 km
Change 54 minutes to hours: $\frac{54}{60} = \frac{9}{10}$ hours
Let t = time it takes to get to his friend's house
Thus $\frac{9}{10} -t$ = time it takes to return home
Distance to Friend's house = Distance back home
$4t=5( \frac{9}{10} -t)$ distance = speed x time
$4t= \frac{9}{2} -5t$ distributive property
$9t= \frac{9}{2}$ add 5t to both sides of the equation
$t= \frac{1}{2}$ divide both sides by 9
To find the distance to the friend's house 4 x 1/2 = 2 km

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Asparrow flies to see a friend at a speed of 4km/h. his friend is out, so the sparrow immediately returns home at a speed of 5km/h. the complete journey took 54 minutes. how far away does his friend live?

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