Aspring on a horizontal surface can be stretched and held 0.6 m from its equilibrium position with a force of 78 n. a. how much work is done in stretching the spring 5.5 m from its equilibrium position? b. how much work is done in compressing the spring 1.5 m from its equilibrium position?

Step-by-step explanation:

x = 0.6 m

F = 78 N

Let k be the spring constant.

F = k x

78 = 0.6 k

k = 130 N/m

(a)

x = 5.5 m

W = 0.5 kx²

W = 0.5 x 130 x 5.5 x 5.5

W = 7865 J

(B) x = 1.5 m

W = 0.5 kx²

W = 0.5 x 130 x 1.5 x 1.5

W = 146.25 J

(x + 0, y − 4), 180° rotation, reflection over the y-axis (A)

Step-by-step explanation:

(x + 0, y − 4), 180° rotation, reflection over the y-axis Is right because i got it right on my test. Option A. Check your options because they could be mixed up so don't rely on the answer choice look at the actual answer.