Asquare poster has a side length of 26 in. drawn on the poster are four identical triangles. each triangle has a base of 8 in. and a height of 8 in. children play a game in which they each wear a blindfold and throw a dart at the poster. a player whose dart lands inside a triangle wins a prize. assuming that a player's dart will always land on the poster, what is the probability of the dart landing in a triangle?

To find the probability of landing on a triangle, you will want find the combined areas of the triangles and the total area of the square target.

Divide the area of the combined areas and the total area to find the probability of landing on a triangle.

A = 1/2bh
      1/2 x 8 x 8
A = 32 square inches
32 x 4
128 square inches (areas of triangles)

A = bh
     26 x 26
A = 676 square inches

128/676 = 0.189

There is an approximate probability of 0.19 of hitting a triangle.

The answer is 0.19 (just took the test)

Step-by-step explanation:

Formula: 1/2bh

so it will be 1/2 * 8 * 8 (8 is from the base and height of the triangle)

= 32

Then you do 32 * 4 which equals 128 (this is the area of the triangles)

Next

Formula: bh

26*26 (the side lengths of the square poster)

= 676

Lastly:

128/676 (divide)

=0.189 --> which rounds to 0.19

buut smalll n/ts momnts

Step-by-step explanation: