Mathematics: Assume each newborn baby has a probability of approximately 0.55 of being female and 0.45 of being male. for a family with three children, let x equal number of children who are girls. a. identify the three conditions that must be satisfied for x to have the binomial distribution. b. identify n and p for the binomial distribution. c. find the probability that the family has one girl and two boys.

Parallel never cross perpendicular is a 90 degree angleits neither if its not 90 degree or never crossing...

Assume each newborn baby has a probability of approximately

jasonoliva13

13.03.2022

1. There must be exactly two possible outcomes (girl, boy).

2. Repeated trials must be independent.

3. The probabilities of the two outcomes don't change from trial to trial.

n = 3 (there are 3 children "generated")

p = 0.55 (the probability that a child is a girl)

The probability that a family of 3 consists of one girl and two boys is

$_3C_1 \times (.55)^1 \times (.45)^2 = 3 \times .55 \times .2025 = 0.334125$

In general, the probability that a binomially distributed random variable X is equal to r is

$_nC_r \times p^r \times (1-p)^{n-r}$

0,0(0 оценок)