krystlemiller11211
28.07.2019 •
Mathematics
Assume that 10% of people are left-handed. suppose 12 people are selected at random. what's the probability that the majority is right-handed?
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Ответ:
Ответ:
11-(-2)+= 11-(-2)t
-49-29= -78
Step-by-step explanation:
11-(-2)+=
11+2t
-49-29=
-(49+29)
-78