Mathematics: Assume that a procedure yields a binomial distribution with a trial repeated n = 9 times. Find the probability of x = 4 successes given the probability p = 0.59 of success on a single trial. (Report answer accurate to 4 decimal places.) P ( 4 ) =

Assume that a procedure yields a binomial distribution

plzzhelp7931

21.01.2022

We have a closed formula to get the probability of having a certain number of successes over repeated trials following a binomial distribution.

The formula is

$\displaystyle P(X=k)=\binom{n}{k}p^k(1-p)^{n-k}$

Where:

is the random variable

is the number of trials

is the number of desired successes

is the probability of success

So, in your case, the probability becomes

$\displaystyle P(X=4)=\binom{9}{4}0.59^4(0.41)^{5}\approx 0.1768$

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jaylen2559

19.09.2022

P = w + 5

Step-by-step explanation:

perimeter = width + length

P = w + 5

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