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mari8493
25.04.2020 •
Mathematics
Assume that both populations are normally distributed. a) Test whether mu 1 not equals mu 2 at the alpha equals 0.05 level of significance for the given sample data. b) Construct a 95% confidence interval about mu 1 minus mu 2. Sample 1 Sample 2 n 19 19 x overbar 16.2 14.1 s 4.5 3.1
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Ответ:
Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
Solution to the problem
For this case the confidence interval is given by:
And the degrees of freedom are given by:
We want a 95% of confidence o then the significance level is 1-0.95 =0.05 and
if we find a critical value in the t distribution with 36 degrees of freedom we got:
And replacing we got:
Ответ: