Assume that thermometer readings are normally distributed with a mean of 0°c and standard deviation of 1.00°c. a thermometer is randomly selected and tested. for the case below, draw a sketch, and find the probability of the reading. (the given values are in celsius degrees)

between 0.50 and 2.00

the probability of getting a reading between 0.50c and 2.00c is

  0.2857

Step-by-step explanation:

The probability of interest is the area under the probability density curve between the z-values associated with the temperature limits of interest.

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The first attachment shows a "sketch" of the distribution and the area of the portion of interest. (It also shows the probability as 0.2858.)

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The second attachment shows the table values of interest for this problem. The z-values that we want to look for in the table are ...

  z1 = (0.50° -0°)/1.00° = 0.50

and

  z2 = (2.00° -0°)/1.00° = 2.00

The area of the probability density function to the left of each of these z-values is given in the table, so the area between them is the difference of table values:

  0.9772 -0.6915 = 0.2857

The probability of a reading between 0.50 and 2.00 is about 0.2857.

Emilias inequality, x<6 is correct because the number of hours is less than it equal to 6. Emilias number line is correct. The endpoint is correctly filled in and the number line should be shaded to the left of the endpoint.