rehel1546
18.01.2021 •
Mathematics
Assume the figure below is a rhombus:
If DE=16x-3, EF=9x+11, and DF=52, find HG
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Ответ:
9514 1404 393
HG = √165 ≈ 12.8
Step-by-step explanation:
All sides of the rhombus are the same length, so ...
DE = EF
16x -3 = 9x +11
7x = 14
x = 2
DE = 16(2) -3 = 29
Because the diagonals bisect each other, we have ...
HF = DF/2 = 52/2 = 26
We know side GF is 29, so ...
HG² + HF² = GF²
HG² = GF² -HF² = 29² -26² = 165
HG = √165 ≈ 12.8 . . . . rounded to tenths
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