Mathematics: Assuming that the sample mean carapace length is greater than 3.39 inches, what is the probability that the sample mean carapace length is more than 4.03 inches

Assuming that the sample mean carapace length

Ответ:

Lianabel0517

09.08.2021

Mathematics

The answer is "".

Step-by-step explanation:

Please find the complete question in the attached file.

We select a sample size n from the confidence interval with the mean $\mu$ and default $\sigma$ , then the mean take seriously given as the straight line with a z score given by the confidence interval

$\mu=3.87\\\\\sigma=2.01\\\\n=110\\\\$

Using formula:

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

The probability that perhaps the mean shells length of the sample is over 4.03 pounds is

$P(X4.03)=P(z\frac{4.03-3.87}{\frac{2.01}{\sqrt{110}}})=P(z0.8349)$

Now, we utilize z to get the likelihood, and we use the Excel function for a more exact distribution

$=\textup{NORM.S.DIST(0.8349,TRUE)}\\\\P(z$

the required probability: P(z0.8349)=1-P(z

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Ответ:

mclendenen8011

17.02.2022

Mathematics

I have nothing to go off on, but an equation that would fit for (1,2) is y=2x.

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hope it helps

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Assuming that the sample mean carapace length is greater than 3.39 inches, what is the probability that the sample mean carapace length is more than 4.03 inches

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