21hendlill
28.10.2019 •
Mathematics
Astandardized exam's scores are normally distributed. in a recent year, the mean test score was 1548 and the standard deviation was 319. the test scores of four students selected at random are 1990, 1280, 2240, and 1450. find the z-scores that correspond to each value and determine whether any of the values are unusual.
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Ответ:
The Zscore value is the number of standard deviations a given score is from the mean of the distribution. The Zscore values are ; 1.386, - 0.840, 2.169 and -0.307 respectively.
None of the values are unusual.
Given the Parameters :
Mean, μ = 1548Standard deviation, σ = 319The test scores, X ; 1990, 1280, 2240, 1450
Recall :
Zscore = (X - μ) ÷ σFor X = 1990 ;
Zscore = (1990 - 1548) / 319 = 1.386
For X = 1280 ;
Zscore = (1280 - 1548) / 319 = - 0.840
For X = 2240 ;
Zscore = (2240 - 1548) / 319 = 2.169
For X = 1450 ;
Zscore = (1450 - 1548) / 319 = - 0.307
Therefore, the corresponding Zscore values for 1990, 1280, 2240 and 1450 are 1.386, -0.840, 2.169 and -0.307 respectively
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Ответ:
Step-by-step explanation:
z-score is:
z = (x − μ) / σ
For the four students:
z = (1990 − 1548) / 319 = 1.39
z = (1280 − 1548) / 319 = -0.84
z = (2240 − 1548) / 319 = 2.17
z = (1450 − 1548) / 319 = -0.31
z-scores are considered significant if they are less than -2 or greater than 2. So the third student's score is unusual.
Ответ:
3.5*2.5=8.75
Step-by-step explanation:
3.5 and 2.5: two digit numbers
8.75: between 8 and 10