Astudent takes 10 exams during a semester and receives the following grades 90 85 97 76 89 58 82 102 70 and 67 what would the five number summary used in a boxplot

Formula using a boxplot

Minimum = the lowest element of set

First Quartile = (n+1)/4

Median = (n+1)/2

Third Quartile = 3(n+1)/4

Maximum = the highest element of set.

 

Solution:

Arrange the given in order. (58, 67, 70, 76, 82, 85, 89, 90, 97, 102),

The five number summary of (90, 85, 97, 76, 89, 58, 82, 102, 70, and 67) is,

Minimum = 58

First Quartile = (10+1)/4 = 2.75 (or 3) getting this answer you need to go back to the arranged given numbers and look for the 3rd number which is 70

Median:  = (82+85)/2 = 83.5

Third Quartile = 3(10+1)/4 8.25 or 8th which is 90 in the arranged numbers.

Maximum = 102

⅔ ÷ ⅛=
when you divide two fractions, make sure to flip flop the second one and change the division sign to multiplication.
⅔ × 8=
(8 over 1 is the same as 8; it's a whole number if divided, or turned into a decimal)
the 16/3 (in fraction form; if you want to convert into a decimal simply divide both numbers and you get 5.3 repeating)
-How did I get this answer?
Simply multiply the numerator of one fraction with the numerator of the other, and the denominator of one fraction with the denominator of the other fraction. In other cases, you might get a fraction you need to simplify, or even convert to a decimal, if required.