Braxtonw875
21.11.2019 •
Mathematics
Astudy was done to determine the average number of homes that a homeowner owns in his or her lifetime. for the 60 homeowners surveyed, the sample average was 4.2 and the sample standard deviation was 2.1. calculate the 95% confidence interval for the true average number of homes that a person owns in his or her lifetime.
a) (3.90, 4.50)
b) (3.66, 4.74)
c) (4.01, 4.39)
d) (3.67, 4.73)
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Ответ:
D) (3.67, 4.73)
Step-by-step explanation:
Confidence Interval for the true average number of homes that a person owns in his or her lifetimecan be calculated using M±ME where
M is the average number of home owned (4.2)ME is the margin of error from the meanAnd margin of error (ME) can be calculated as
ME= where
z is the corresponding statistic in the given confidence level(1.96)s is the standard deviation of the sample(2.1)N is the sample size (60)Putting the numbers we get ME=≈0.53
Then the 95% confidence interval is 4.2±0.53 or (3.67, 4.73)
Ответ:
123123
Step-by-step explanation:
43123