Mathematics: Astudy was done to investigate the population of a certain species of animal over time. the correlating linear model is shown below, where x represents the number of years after 1955, and y represents the number of that certain species. interpret the y-intercept. y = 5,000 + 500x a. there were 1,000 of that species in 1955. b. there were 10,000 of that species in 1955. c. there were 500 of that species in 1955. d. there were 5,000 of that species in 1955.

Astudy was done to investigate the population of

taleiayarbough4544

10.03.2022

D. There were 5,000 of that species in 1955.

Step-by-step explanation:

The initial population of the species is equal to the y-intercept of the first-order polynomial. Hence, the right answer is D.

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TwentyOnePawPrints21

13.04.2020

The solution is:

$\:\frac{-1}{8}-\left(-6\frac{7}{8}\right)=\frac{27}{4}$

Step-by-step explanation:

As your expression is a little ambiguous, so I am assuming that your expression is

$\frac{-1}{8}-\left(-6\frac{7}{8}\right)$

solving

$\frac{-1}{8}-\left(-6\frac{7}{8}\right)$

$\frac{-1}{8}-\left(-\frac{55}{8}\right)$ ∵ $6\frac{7}{8}=\frac{55}{8}$

$=\frac{-1}{8}+\frac{55}{8}$

$=\frac{-1+55}{8}$

$=\frac{54}{8}$

$=\frac{27}{4}$

Therefore, the answer is:

$\:\frac{-1}{8}-\left(-6\frac{7}{8}\right)=\frac{27}{4}$

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