Aswimming pool chargesv$6 for adults and $4 for children. on a particular day they made $1326 in admissions. if a tital of 289 people paid to swim, there must have been

To solve this we can use the following system of equations: 
6a + 4c = 1326 
a + c = 289 
When a = adults and c = children. 
First we can take the second equation and subtract a from both sides to get  
c = 289 - a. Then substitute that into the first equation to get  
6a + 1156 - 4a = 1326. Next combine like terms to get 2a + 1156 = 1326. 
Now subtract 1156 from both sides to get 2a = 170. To get the final answer for a divide both sides by 2 to get a = 85. 
To get the value for c, now substitute it into the second equation to get 
85 + c = 289. Subtract 85 from both sides to get c = 201. 
85 adults and 201 children went swimming that day. Hope this helps!

GCF of numbers is the highest number that can divide both numbers. The expression for the sum of 48 and 30 is:

The numbers are given as 48 and 30

So, the expression is

Their GCF is 6. So, we have:

Factor out 6

Solve the expression in brackets

Evaluate the product

Hence, the expression is:

Read more about GCF at:

link