qveenvslayin
21.07.2019 •
Mathematics
Asystem of equations consists of two lines. one line passes through (-1, 3) and (0, 1). the other line passes through (1, 4) and (0, 2). determine of the system has no solution, one solution, or an infinite number of solutions.
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Ответ:
y = mx + b
Where,
m = (y2-y1) / (x2-x1)
For (-1, 3) and (0, 1):
We look for the value of m:
m = (1-3) / (0 - (- 1))
m = (- 2) / (0 + 1)
m = -2
We look for the value of b:
1 = m (0) + b
b = 1
The line is:
y = -2x + 1
For (1, 4) and (0, 2):
We look for the value of m:
m = (2-4) / (0-1)
m = (- 2) / (- 1)
m = 2
We look for the value of b:
2 = m (0) + b
b = 2
The line is:
y = 2x + 2
The system of equations is:
y = -2x + 1
y = 2x + 2
the system has one solution
Ответ:
A. 27
Step-by-step explanation:
21 x 3 = 63
9 x 3 = 27