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05.08.2019 •
Mathematics
At 10: 00 a.m. two boys start out on their bikes to meet each other from towns located 68 miles apart. at 1: 00 p.m. they meet. if one boy traveled 3 miles per hour faster than the other, what was the rate of speed of each boy?
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Ответ:
a + 3 = speed of 2nd boy
d = speed X time ... time is 3 hrs
68 = 3a + 3(a + 3)
6a = 59
a = 59/6 = 9 5/6 miles per hour
a + 3 = 12 5/6 miles per hou
Ответ:
The rate of each boys are as follows:
The boy at slower speed = 9.8 mph (slow speed)
The boy at faster speed= 12.8 mph (faster speed)
Calculation of speedSpeed can be defined as the distance covered per unit time. That is, speed = distance/time.
Since the faster boy travels 3 miles per hour faster than the other, therefore
slower speed= x and
faster speed= x + 3
The total time for each boy = 3 hours
To find out the distance for each boy, you must multiply the 3 hours (time) and speed together.
so distance = time*speed
Therefore,
slower distance = 3x
faster distance = 3(x +3)
Then you can add them together to get the total distance.
To Solve for slow speed(x).
3x + 3(x + 3) = 68
3x + 3x + 3×3 = 68
6x + 9 = 68 add like terms
6x = 68 - 9
6x = 59
x = 59/6 = 9.8 mph (slow speed)
Therefore, faster speed,
x + 3 = 12.8 mph (faster speed)
Therefore, the rate of each boys are 9.8 mph (slow speed) and 12.8 mph (faster speed).
Learn more about speed here:
Ответ:
distance = speed * time
= (15mph)*(12minutes/60 minutes per hour)
= (15mph)*(0.2 hours)
= 3 miles
trip downhill back home is along the same path
so the trip downhill was also equal to 3 miles.
So the the entire trip was a distance of 6 miles
3 miles uphill and 3 miles downhill.
So the average speed = (15mph uphill + 30mph downhill)/2
= 45 mph/2
= 22.5 mpg
So the average speed of the entire trip uphill and downhill is 22.5 mph