Mathematics: At 10:57 A.M. A submarine was at a depth of feet. Its depth then changed at a rate of -8 feet per minute. What was its depth at 11:03 A.M.? Group of answer choices

At 10:57 A.M. A submarine was at a depth of feet.

Ответ:

aprilreneeclaroxob0c

02.02.2022

48 feet

Step-by-step explanation:

First we need to get the total minutes used by the submarine from 10:57 A.M to 11:03 A.M. The total minutes used within the specified period of time is 6 minutes.

If its depth then changed at a rate of 8 feet per minute, the submarine depth after 6 minutes will be expressed as shown;

8 feet = 1minute

x feet = 6 minutes

cross multiply;

x * 1 = 8 * 6

x = 48 feet

Hence the submarine depth at 11.03AM is 48 feet

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Ответ:

tatayanamarie5909

20.10.2020

Mathematics

$\bf \textit{volume of a cylinder}\\\\
V=\pi r^2 h~~
\begin{cases}
r=radius=\frac{diameter}{2}\\
h=height\\
----------\\
diameter = d\\
r=\frac{d}{2}
\end{cases}\implies V=\pi \left( \frac{d}{2} \right)^2 h
\\\\\\
V=\pi \left( \frac{d^2}{2^2} \right)h\implies V=\cfrac{\pi d^2 h}{4}\implies 4V=\pi d^2 h\implies \cfrac{4V}{\pi d^2}=h$

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At 10:57 A.M. A submarine was at a depth of feet. Its depth then changed at a rate of -8 feet per minute. What was its depth at 11:03 A.M.? Group of answer choices

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