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bm42400
24.10.2019 •
Mathematics
At 9: 00 on saturday morning, two bicyclists heading in opposite directions pass each other on a bicycle path.the bicyclist heading north is riding 4 km/hour faster than the bicyclist heading south. at 10: 15, they are 40 km apart. find the two bicyclists’ rates.
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Ответ:
y be the speed of bicyclist B (heading south)
since A is 5km/hr faster than B
x = y + 5 equation 1
time = 9 to 10:45 = 1.75hours since the distance is 47.25km then,
x(1.75) + y(1.75) = 47.25 ---equation 2
substitute equation 1 to 2 (y+5)(1.75) + 1.75y
= 47.25 1.75y +8.75 + 1.75y
= 47.25 3.5y
= 47.25 - 8.75 3.5y
= 38.5
y = 11km/hr
substitute to equation 1
x = y + 5 x
= 11 + 5 x
= 16km/hr
Ответ:
f(x)=0*(1.025)^x
Step-by-step explanation:
i took a test and got it wrong :o this was the answer