Mathematics: At a certain time in a zoo, the number of heads and the number of legs of tigers and peacocks were counted and it was found that there were 47 heads and 152 legs, find the number of tigers and peacocks in the zoo

At a certain time in a zoo, the number of heads

husk84

13.03.2020

Given:

The probability of landing A is 0.70.

The probability of landing B is 0.60.

The probability of landing both is 0.50.

To find:

The probability of landing A given it lands B.

Solution:

We have,

P(A) = 0.70

P(B) = 0.60

$P(A\cap B) = 0.50$

The probability of landing A given it lands B is

$P\left(\dfrac{A}{B}\right)=\dfrac{P(A\cap B)}{P(B)}$

$P\left(\dfrac{A}{B}\right)=\dfrac{0.50}{0.60}$

$P\left(\dfrac{A}{B}\right)=\dfrac{5}{6}$

$P\left(\dfrac{A}{B}\right)=0.8333...$

$P\left(\dfrac{A}{B}\right)\approx 0.83$

Therefore, the probability of landing A given it lands B is about 0.83.

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