Mathematics: At a certain university, 42% of the students are women, and 18% are engineering majors. of the engineers, 22% are women. if a student at this university is selected at random, what is the probability that the selected person is either a woman or an engineering major? 0.6.03960.5604

At a certain university, 42% of the students are

amanda2517

15.03.2022

0.5604

Step-by-step explanation:

Let A represents the students who are women and B represents the students who are engineering majors.

Then , we have given that $P(A)=0.42\ ;\ P(B)=0.18\ ;\ P(A|B)=0.22$

By formula , $P(A\cap B)=P(A|B)\times P(B)=0.22\times0.18=0.0396$

Using formula, $\text{P(A or B)=P(A)+P(B) - P(A and B)}$ , we have

$\text{P(A or B)}=0.42+0.18-0.0396=0.5604$

Hence, the probability that the selected person is either a woman or an engineering major = 0.5604

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nicolascorrea0207

15.09.2022

do your homework by yourself. don't go asking, your going to fail college if you just ask for other peoples .

step-by-step explanation:

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