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williamsa24mr238org
25.01.2021 •
Mathematics
At a local coffee shop, the manager has determined that 56% of drink orders are for specialty espresso drinks and 44% are for plain coffee. The manager also noted that 40% of customers order food. For customers who purchase the specialty espresso drinks, 35% also purchase a food item, and for customers who purchase plain coffee, 30% also purchase a food item. What is the probability that a randomly chosen customer will purchase a specialty espresso drink and a food item?
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Ответ:
0.196
Step-by-step explanation:
Let :
Expresso drink = A
Plain coffee = B
Food = F
P(A) = 0.56
P(B) = 0.44
P(F) = 0.40
P(F|A) = 0.35
P(F|B) = 0.30
Probability that a customer purchases a specialty expresso coffee and a food item :
P(F|A) =. P(F n A) / P(A)
P(F n A) = P(F|A) * P(A)
P(F n A) = 0.35 * 0.56
P(F n A) = 0.196
Ответ:
Sure I will play truth or dare