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jasbutt015p2pqp8
13.05.2021 •
Mathematics
At a local seaside, a vendor sells single-cone ice-creams for $3 and double-cone ice-creams for $4.50. The vendor stocks a maximum of 70 single cones and a maximum of 45 double cones. For the afternoon he expects to sell no more than 50 ice-creams.
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Ответ:
The answer is below
Step-by-step explanation:
Let x represent the number of single cone ice cream and let y represent the number of double cone ice cream.
Since the vendor stocks a maximum of 70 single cones and a maximum of 45 double cones. hence:
0 < x ≤ 70, 0 < y ≤ 45 (1)
The vendor expects to sell no more than 50 ice creams, hence:
x + y ≤ 50
Plotting the constraint using geogebra online graphing tool, we can see that the solution to the problem is at (5, 45)
Since the vendor sells single-cone ice-creams for $3 and double-cone ice-creams for $4.50, hence:
Revenue = 3x + 4.5y
At the point (5, 45), the revenue is:
Revenue = 3(5) + 4.5(45) = $217.5
Ответ:
congruent,
Step-by-step explanation:
coz if u put them the same way they are the same