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biggiecheese93
15.10.2020 •
Mathematics
At a NASCAR racetrack, the distance per lap is 2 miles. Lou Lambert drives his car at a constant rate of 160 miles per hour. Ralph Redding drives his car at a constant rate of 170 miles per hour. How long will it take before Ralph gains 2 laps in relation to Lou?
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Ответ:
24 minutes
Step-by-step explanation:
Given:
Distance per lap = 2 miles
Speed of Lou Lambert = 160 miles/hr
Speed of Ralph Redding = 170 miles/hr
Speed difference between the two = 170 - 160 = 10 miles/hr
Therefore, we can say that Ralph gains 10 miles in 60 minutes over Lou.
We have to find the time in which Ralph will gain 2 laps i.e. 2
2 = 4 miles.
Let us use unitary method to find the required time.
10 miles are gained by Ralph in 60 minutes
1 mile will be gained in![\frac{60}{10} = 6\ minutes](/tpl/images/0806/4411/f69fc.png)
4 miles will be gained in 6
4 = 24 minutes
Ответ:
5.7 cm or 2 1/4 in
Step-by-step explanation:
Your tape measure is not shown.
On my tape measure, 5.7 cm is the closest mark. On the inch scale, 2 1/4 inches is the next-closest mark.
On a tape measure graduated in 1/32 inch between 2 and 3 inches, you can find the closest mark by rounding to the nearest 32nd:
2.23607 × 32 ≈ 71.55 ≈ 72 --- 32nds of an inch
72/32 = 2 1/4 . . . . the closest mark on an inch ruler graduated in 32nds
__
For a ruler graduated in millimeters, you can find the closest millimeter in the same way. There are 25.4 mm to the inch.
2.23607 in × 25.4 mm/in ≈ 56.80 mm ≈ 57 mm
57 mm = 5.7 cm . . . closest mark on metric scale
__
When we check the error, we find the metric mark is closer than the inch mark.
5.7 cm ≈ 2.24409 in . . . . error of 0.00802 in
2 1/2 in = 2.25000 in . . . error of 0.01393 in