At an auto dealership, 8 new cars of different colors are randomly lined up in front of the building. what is the probability that the first car is red, the second car is blue, and the third car is black?

Hey Dftackle, 

Lets solve your problem step by step. 

To solve the problem we have analyze the question carefully. 

As we are aware: At an auto dealership, 8 new cars of different colors are randomly lined up in front of the building. 

Therefore, lets use a variable "c" to represent the different colors of cars as they are randomly lined up in front of the auto dealership. 

We know that there are 8 new cars, so can represent this statement. 

       Now lets examine the next line. 

We have to find the probability of the first car being red, the second car being blue, and the third car being black. 

Since we are only given three cars, our fraction changes to : . 

As a result, the probability  of the first car being red, the second car being blue, and the third car being black is because we do not know any more information about the remaining cars. 

Hope this helps, 

        AnthrαX  

56.0% not wiped

Step-by-step explanation:

150° = 5π/6 rad

Area wiper covers

Aw = ½(5π/6)24² - ½(5π/6)2² = 238⅓π in² ≈ 748.75 in²

Area of window

(66 - 54)/2 = 6in

h = √(29² - 6²) = 28.37 in

A = 28.37(54 + 6) = 1,702.35

percentage not cleared by wiper is

(1,702.35 - 748.75) / 1,702.35 = 0.56016 ≈ 56.0%

Arc length ACB = rθ = 24(5π/6) = 20π ≈ 62.8 inches

inner arc length = 2(5π/6) = 5π/3 ≈ 5.23 inches