maleah12x
18.01.2020 •
Mathematics
Determine the zeros of x^2 + 4x - 16 = -2x .
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Ответ:
x^2 + 6x - 16 = 0 Add 2x to both sides
and use the equation: x = -b ± (sqrt((b^2 - 4(a)(c/2a and Ax^2 + Bx + C = 0
A = 1
B = 6
C = -16
x = -3 ± (sqrt((36 + 64)))/2
x = -3 ± (sqrt(100))/2
x = -3 ± 5
x = 2
-and-
x = -8
Ответ:
Ответ:
I think its y=mx+b
Step-by-step explanation: