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somedudeontheIn
30.11.2019 •
Mathematics
At noon a truck leaves prescott, az driving east at a speed of 40 miles per hour. an hour later, a second truck leaves prescott driving north at a speed of 60 miles per hour. at what rate is the distance between the trucks increasing at 2: 00 p.m. that day?
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Ответ:
60 miles per hour
Step-by-step explanation:
The right angle triangle formed is shown in the attached photo.
Let the first truck be truck A and the second truck be truck B
At noon, truck A moved from Prescott, AZ at a speed of 40 miles per hour. It travelled for one hour before truck A moved.
Distance = speed × time.
This means that distance moved by truck A in one hour is 40 × 1 = 40 miles. So at 1 pm, truck A had moved 40 miles. At 2pm, truck A would have moved another 40 miles because it's another one hour and the speed is still 40 miles per hour. Total distance moved by truck A at 2pm = 40 + 40 = 80 miles
At 1 pm, truck B moved for one hour at a speed of 60 miles per hour.
Distance moved by truck B = 60 × 1 = 60 miles.
So at 2pm, truck be has moved 60 miles.
To determine the distance,x between them at 2pm, we will find the hypotenuse of the triangle.
x^2 = √(80^2 + 60^2)
x = 100 miles
So at 2pm, they are already 100 miles apart.
So at 1pm, they were 40 miles apart and 1 hour later, at 2pm, they were 100 miles apart. Therefore, the distance increased by 60 miles per hour at 2pm
Ответ:
slope= 4
Step-by-step explanation:
rise=20 run= 5 divide =4