Mathematics: At the peak of a roller coaster ride, the rider s watch flew off his wrist. The height h in feet of the watch, t seconds after he lost it, is given by y= -16x^2 + 32x + 48. How many seconds did it hit the ground?

At the peak of a roller coaster ride, the rider s

Ответ:

boi3456

27.04.2021

$3 \: s$

Step-by-step explanation:

$y = - 16 {x}^{2} + 32x + 48 \\ 0 = \frac{ - 16 {x}^{2} + 32x + 48 }{ - 16} \\0 = {x}^{2} - 2x - 3 \\ 0= {x}^{2} - 3x + x - 3 \\ 0= x(x - 3) + 1(x - 3) \\0 = (x + 1)(x - 3) \\ \\ x + 1 = 0 \\ x = - 1 \\ x - 3 = 0 \\ x = 3$

Hope this helps you.

Can I have the brainliest please?

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Ответ:

kelleemaebarnha

17.12.2021

Mathematics

Start with the parent function y=1/x^2

Add 3 to x in the denominator, because the graph is shifted left 3.

Add 1 to the fraction, because the graph is shifted up 1 unit

Step-by-step explanation:

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At the peak of a roller coaster ride, the rider's watch flew off his wrist. The height h in feet of the watch, t seconds after he lost it, is given by y= -16x^2 + 32x + 48. How many seconds did it hit the ground?

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At the peak of a roller coaster ride, the rider's watch flew off his wrist. The height h in feet of the watch, t seconds after he lost it, is given by y= -16x^2 + 32x + 48. How many seconds did it hit the ground?​

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At the peak of a roller coaster ride, the rider's watch flew off his wrist. The height h in feet of the watch, t seconds after he lost it, is given by y= -16x^2 + 32x + 48. How many seconds did it hit the ground?