At what point on the curve y = 2 + 2ex − 4x is the tangent line parallel to the line 4x − y = 3? (x, y) =

{ln 4, (2 + 2e^ln 4 − 4 ln 4)} or (1.39, 4.45)

Step-by-step explanation:

From this equation 4x − y = 3

-y = 3 - 4x

then, y = 4x - 3

From line equation y = mx + b

Therefore, the slope is 4

Since the are parallel line, they will have same slope

Finding the derivative of y = 2 + 2e^x − 4x

y = 2 + 2e^x − 4x

y' = 0 + 2e^x - 4

Therefore,

4 = 2e^x - 4

4 = e^x

x = ln 4 = 1.39

To find the y coordinate

y = 2 + 2e^x − 4x

y = 2 + 2e^ln 4 − 4 ln 4

y = 4.45

Hence, they are parallel at point (1.39 and 4.45)

205

Step-by-step explanation:

((2x6)-7+9)^2+45/5

= ((12)-7+9)^2+45/5

= (12-7+9)^2+45/5

= (14)^2+45/5

= 196+45/5

= 196 + 9

= 205