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magdlenejekkar
22.05.2021 •
Mathematics
At which value(s) of x does the graph of the function F(x) have a vertical asymptote? Check all that apply.
F(x) = x/(x+2)(x-1)
o x=10
o x=-2
o x=0
o x=-1
o x=2
o x=1
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Ответ:
x = - 2, x = 1
Step-by-step explanation:
Given
f(x) =![\frac{x}{(x+2)(x-1)}](/tpl/images/2371/3130/f4d6c.png)
The denominator cannot be zero as this would make f(x) undefined.
Equating the denominator to zero and solving for x gives the values that x cannot be and if the numerator is non zero for these values then they are vertical asymptotes.
(x + 2)(x - 1) = 0
x + 2 = 0 ⇒ x = - 2
x - 1 = 0 ⇒ x = 1
Vertical asymptotes occur at x = - 2 and x = 1
Ответ:
Try 8.5 :)
hope this is correct
Step-by-step explanation: